Advertisements
Advertisements
Question
The area of a regular hexagon of side ‘a’ is the sum of the areas of the five equilateral triangles with side a.
Options
True
False
Solution
This statement is False.
Explanation:
Given: The side of a regular hexagon is ‘a’.
As we know that the regular hexagon is divided into six equilateral triangles.
So, Area of regular hexagon = Sum of area of the six equilateral triangles.
APPEARS IN
RELATED QUESTIONS
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
Find the area of a quadrilateral ABCD is which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
Area of PQRS = Area of PQR + Area of ΔPQS = (6+9.166)𝑐𝑚2=15.166𝑐𝑚2
Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and 26 cm. Find the area of the trapezium.
Find the area of a rhombus whose perimeter is 80 m and one of whose diagonal is 24 m.
The sides of a triangle are 7 cm, 9 cm and 14 cm. Its area is
The sides of a triangle are 11 cm, 15 cm and 16 cm. The altitude to the largest side is
A land is in the shape of rhombus. The perimeter of the land is 160 m and one of the diagonal is 48 m. Find the area of the land.
The perimeter of an equilateral triangle is 60 m. The area is ______.
The length of each side of an equilateral triangle having an area of `9sqrt(3)`cm2 is ______.