Advertisements
Advertisements
Question
The critical path of the following network is
Options
1 - 2 - 4 - 5
1 - 3 - 5
1 - 2 - 3 - 5
1 - 2 - 3 - 4 - 5
Solution
1 - 2 - 3 - 4 - 5
Explanation:
1 - 2 - 4 - 5 ⇒ EFT = 20 + 12 + 10 = 42
1 - 3 - 5 ⇒ EFT = 25 + 8 = 33
1 - 2 - 3 - 5 ⇒ EFT = 20 + 10 + 8 = 38
1 - 2 - 3 - 4 - 5 ⇒ EFT = 20 + 10 + 5 + 10 = 45
APPEARS IN
RELATED QUESTIONS
Draw the network for the project whose activities with their relationships are given below:
Activities A, D, E can start simultaneously; B, C > A; G, F > D, C; H > E, F.
Draw the event oriented network for the following data:
Events | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
Immediate Predecessors | - | 1 | 1 | 2, 3 | 3 | 4, 5 | 5, 6 |
The following table gives the activities of a project and their duration in days
Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 |
Duration | 5 | 8 | 6 | 7 | 5 | 4 | 8 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
In constructing the network which one of the following statements is false?
In a network while numbering the events which one of the following statements is false?
Which of the following is not correct?
In the context of network, which of the following is not correct
The objective of network analysis is to
In critical path analysis, the word CPM mean
The following table gives the characteristics of the project
Activity | 1 - 2 | 1 - 3 | 2 - 3 | 3 - 4 | 3 - 5 | 4 - 6 | 5 - 6 | 6 - 7 |
Duration (in days) |
5 | 10 | 3 | 4 | 6 | 6 | 5 | 5 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.