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Question
The diameter of the circle is 52 cm and the length of one of its chord is 20 cm. Find the distance of the chord from the centre
Solution
Length of the chord = 20 cm
AC = `20/2`
= 10 cm
In ΔOAC, OC2 = OA2 – AC2
= 262 – 102
= (26 + 10)(26 – 10)
= 36 × 16
OC = `sqrt(30 xx 16)`
= 6 × 4 cm
= 24 cm
Distance of the chord from the centre = 24 cm.
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