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Question
Find the length of the chord of a circle in the following when:
Radius is 13 cm and the distance from the centre is 12 cm
Solution
AC = CB ----(1) (Perpendicular from centre to a chord bisects the chord)
In right t. ACO,
By Pythagoras theorem, OA2 = OC2 + AC2
132 -122 = AC2
AC2 = 169 - 144 = 25
AC = 5 cm
∴ length of chord AB = 2AC (from (1))
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