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Question
Find the length of the chord of a circle in the following when:
Radius is 1. 7cm and the distance from the centre is 1.5 cm
Solution
AC = CB ----(1) (Perpendicular from centre to a chord bisects the chord)
In right Δ ACO,
By Pythagoras theorem, OA2 = OC2 + AC2
AC2 = (1. 7)2 - (1.5)2 = 2.89 - 2.25 =.64
AC = 0.8 cm
∴ length of chord AB = 2AC (from ( 1))
= 2(0.8) = 1.6 cm
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