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Question
Find the length of the chord of a circle in the following when:
Radius is 6.5 cm and the distance from the centre is 2.5 cm
Solution
BA = AC ----(1) (Perpendicular from centre to a chord bisects the chord)
In right Δ OAB,
By Pythagoras theorem, OB2 = OA2 + AB2
AB2 = 6.52 + 2.52
= 42.25 - 6.25 = 36
AB = 6cm
∴ Length of chord BC = 2 AB (from (1))
= 2 (6) = 12 cm
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