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Question
The electric force experienced by a charge of 1.0 × 10−6 C is 1.5 × 10−3 N. Find the magnitude of the electric field at the position of the charge.
Solution
Given:
Magnitude of the charges, q = 1.0 × 10−6 C
Electric force, F = 1.5 × 10−3 N
We know that F = qE
\[\Rightarrow E = \frac{F}{q} = \frac{1 . 5 \times {10}^{- 3}}{1 . 0 \times {10}^{- 6}} \]
\[ = 1 . 5 \times {10}^3\]N/C
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