Advertisements
Advertisements
Question
The seventh root of x divided by the eighth root of x is
Options
x
\[\sqrt{x}\]
\[\sqrt[56]{x}\]
\[\frac{1}{\sqrt[56]{x}}\]
Solution
We have to find he seventh root of x divided by the eighth root of x, so let it be L. So,
`L= (7sqrtx)/(8sqrtx)`
`= (x^(1/7))/(x^(1/8))`
`= x^(1/7-1/8)`
`= x^((1xx8)/(7xx8)-(1 xx7) /(8 xx 7))`
`L = x^(8/56 -7/56)`
`=x^1/56`
`=56sqrtx`
The seventh root of x divided by the eighth root of x is `56sqrtx`
Hence the correct choice is c.
APPEARS IN
RELATED QUESTIONS
Simplify the following:
`(5^(n+3)-6xx5^(n+1))/(9xx5^x-2^2xx5^n)`
Simplify:
`root3((343)^-2)`
Simplify:
`((25)^(3/2)xx(243)^(3/5))/((16)^(5/4)xx(8)^(4/3))`
Prove that:
`sqrt(1/4)+(0.01)^(-1/2)-(27)^(2/3)=3/2`
Find the value of x in the following:
`5^(2x+3)=1`
Which one of the following is not equal to \[\left( \sqrt[3]{8} \right)^{- 1/2} ?\]
If 102y = 25, then 10-y equals
If o <y <x, which statement must be true?
If \[x = \frac{\sqrt{5} + \sqrt{3}}{\sqrt{5} - \sqrt{3}}\] and \[y = \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} + \sqrt{3}}\] then x + y +xy=
If \[x = \sqrt{6} + \sqrt{5}\],then \[x^2 + \frac{1}{x^2} - 2 =\]
