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Question
If 102y = 25, then 10-y equals
Options
- \[- \frac{1}{5}\]
- \[\frac{1}{50}\]
- \[\frac{1}{625}\]
- \[\frac{1}{5}\]
Solution
We have to find the value of `10^-y`
Given that, `10^(2y) = 25` therefore,
`10^(2y) = 25`
`(10^y)^2 = 5^2`
`(10^y)^(2 xx 1/2)= 5^(2 xx 1/2)`
`(10^y)^(2 xx 1/2)= 5^(2 xx 1/2)`
`10^y/1 = 5/1`
`1/5 =1/10^y`
`1/5 =10^-y`
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