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Question
If 3x-1 = 9 and 4y+2 = 64, what is the value of \[\frac{x}{y}\] ?
Solution
We have to find the value of `x/y` for `3^(x-1) = 9.4^(y+2) = 64`
So,
`3^(x-4) = 3 ^2`
By equating the exponent we get
x-1=2
x=2+1
x=3
Let’s take `4^(y+2) = 64`
`4^(y+2) = 4^3`
By equating the exponent we get
y+2 = 3
y=3-2
y=1
By substituting x=3,y=1 in `x/y` we get `3/1`
Hence the value of `x/y` is 3.
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