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Question
The short and long hands of a clock are 4 cm and 6 cm long respectively. Find the sum of distances travelled by their tips in 2 days.
Solution
n 2 days, the short hand will complete 4 rounds.
Length of the short hand = 4 cm
Distance covered by the short hand = 4 × 2π × 6 = 576 π cm
In the same 2 days, the long hand will complete 48 rounds.
Length of the long hand = 6 cm
Distance covered by the long hand = 48 × π × 6 = 576π cm
∴ Total distance covered by the hands = Distance covered by the short hand + Distance covered by the long hand
= 32π + 576π
= 608 π
= 608 × 3.14
= 1909.12 cm
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