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The Vertex of the Parabola (Y − 2)2 = 16 (X − 1) is - Mathematics

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Question

The vertex of the parabola (y − 2)2 = 16 (x − 1) is 

Options

  • (1, 2) 

  •  (−1, 2) 

  •  (1, −2) 

  • (2, 1) 

MCQ

Solution

(1, 2) 

Given:
(y − 2)2 = 16 (x − 1)
Let \[X = x - 1, Y = y - 2\] 

∴ \[Y^2 = 16X\] 

Vertex = \[\left( X = 0, Y = 0 \right) = \left( x - 1 = 0, y - 2 = 0 \right) = \left( x = 1, y = 2 \right)\] 

Hence, the vertex is at (1, 2). 

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Chapter 25: Parabola - Exercise 25.3 [Page 30]

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RD Sharma Mathematics [English] Class 11
Chapter 25 Parabola
Exercise 25.3 | Q 17 | Page 30

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