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Question
The volume of a conical tent is 1232 m3 and the area of the base floor is 154 m2. Calculate the: length of the canvas required to cover this conical tent if its width is 2 m.
Solution
Let l be the slant height of the conical tent, then
`= l=sqrt(h^2+r^2)`
∴ `l= sqrt(h^2+r^2)=sqrt((24)^2+(7)^2)=sqrt(576+49)=sqrt625=25m`
The area of the canvas required to make the tent =`pirlm^2`
∴`pirl=22/7xx7xx25m^2=550m^2`
Length of the canvas required to cover the conical tent of its width 2 m= `550/2=275 m`
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