Question

The zeroes of the quadratic polynomial 16x² – 9 are ______.

Options

• ${\displaystyle \frac{3}{4},\frac{3}{4}}$

• ${\displaystyle -\frac{3}{4},\frac{3}{4}}$

• ${\displaystyle \frac{9}{16},\frac{9}{16}}$

• ${\displaystyle -\frac{3}{4},-\frac{3}{4}}$

Answer 1

The zeroes of the quadratic polynomial 16x² – 9 are ${\displaystyle \underline{-\frac{3}{4},\frac{3}{4}}}$.

Explanation:

16x² – 9 = 0

(4x – 3)(4x + 3) = 0

∴ x = ${\displaystyle \pm \frac{3}{4}}$