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Using suitable identity, evaluate the following:1033 - Mathematics

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Question

Using suitable identity, evaluate the following:

1033

Evaluate

Solution

103= (100 + 3)3

= (100)3 + (3)3 + 3 × 10 × 3 × (100 + 3)  ...[Using identity, (a + b)3 = a3 + b3 + 3ab(a + b)]

= 1000000 + 27 + 900(103)

= 1000027 + 92700

= 1092727

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Chapter 2: Polynomials - Exercise 2.3 [Page 21]

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NCERT Exemplar Mathematics [English] Class 9
Chapter 2 Polynomials
Exercise 2.3 | Q 25. (i) | Page 21

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