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Using suitable identity, evaluate the following: 101 × 102 - Mathematics

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Question

Using suitable identity, evaluate the following:

101 × 102

Evaluate

Solution

101 × 102 = (100 + 1)(100 + 2)

= (100)2 + 100(1 + 2) + 1 × 2  ...[Using identity, (x + a)(x + b) = x2 + x(a + b) + ab]

= 10000 + 300 + 2

= 10302

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Chapter 2: Polynomials - Exercise 2.3 [Page 21]

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NCERT Exemplar Mathematics [English] Class 9
Chapter 2 Polynomials
Exercise 2.3 | Q 25. (ii) | Page 21

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