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Question
What will happen during the electrolysis of aqueous solution of \[\ce{CuSO4}\] by using platinum electrodes?
(i) Copper will deposit at cathode.
(ii) Copper will deposit at anode.
(iii) Oxygen will be released at anode.
(iv) Copper will dissolve at anode.
Solution
(i) Copper will deposit at cathode.
(iii) Oxygen will be released at anode.
Explanation:
During electrolysis following reaction takes place at cathode:
\[\ce{Cu^{2+} + 2e^{-} -> Cu}\]
\[\ce{H^{-} + e^{-} -> 1/2 H_2}\]
Standard electrode potential of \[\ce{Cu^{2+}/Cu}\] is greater than \[\ce{H-/1/2 H2}\] therefore Cu will deposite at cathode.
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