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Question
Why does compound (A) given below not form an oxime?
(A)
Solution
Glucose pentaacetate (structure A) does not have a free –OH group at C, and therefore, cannot be converted to the open chain form to give a free –CHO group and hence it does not form the oxime.
(Structure A)
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\[\begin{array}{cc}
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|\phantom{....}\\
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