SSC (English Medium)
SSC (Marathi Semi-English)
Academic Year: 2021-2022
Date & Time: 26th March 2022, 10:30 am
Duration: 2h15m
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General Instructions :
- All questions are compulsory.
- Use of a calculator is not allowed.
- The numbers to the right of the questions indicate full marks.
- In case of MCQs (Q. No. 1(A)) only the first attempt will be evaluated and will be given credit.
- For every MCQ, the correct alternative (A), (B), (C) or (D) with subquestion number is to be written as an answer.
- Draw proper figures for answers wherever necessary.
- The marks of construction should be clear. Do not erase them.
- Diagram is essential for writing the proof of the theorem.
If ΔABC ∼ ΔDEF and ∠A = 48°, then ∠D = ______.
48°
83°
49°
132°
Chapter: [0.01] Similarity
AP is a tangent at A drawn to the circle with centre O from an external point P. OP = 12 cm and ∠OPA = 30°, then the radius of a circle is ______.
12 cm
`6sqrt(3)` cm
6 cm
`12sqrt(3)` cm
Chapter: [0.03] Circle
Seg AB is parallel to X-axis and coordinates of the point A are (1, 3), then the coordinates of the point B can be ______.
(–3, 1)
(5, 1)
(3, 0)
(–5, 3)
Chapter: [0.05] Co-ordinate Geometry
The value of 2tan45° – 2sin30° is ______.
2
1
`1/2`
`3/4`
Chapter: [0.06] Trigonometry
In ΔABC, ∠ABC = 90°, ∠BAC = ∠BCA = 45°. If AC = `9sqrt(2)`, then find the value of AB.
Chapter: [0.02] Pythagoras Theorem
Chord AB and chord CD of a circle with centre 0 are congruent. If m(arc AB) = 120°, then find the m(arc CD).
Chapter: [0.03] Circle
Find the Y-coordinate of the centroid of a triangle whose vertices are (4, –3), (7, 5) and (–2, 1).
Chapter: [0.05] Co-ordinate Geometry
If sinθ = cosθ, then what will be the measure of angle θ?
Chapter: [0.03] Circle
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In the above figure, seg AC and seg BD intersect each other in point P. If `("AP")/("CP") = ("BP")/("DP")`, then complete the following activity to prove ΔABP ∼ ΔCDP.
Activity: In ΔABP and ΔCDP
`("AP")/("CP") = ("BP")/("DP")` ......`square`
∴ ∠APB ≅ `square` ......Vertically opposite angles
∴ `square` ∼ ΔCDP ....... `square` test of similarity.
Chapter: [0.01] Similarity
In the above figure `square`ABCD is a rectangle. If AB = 5, AC = 13, then complete the following activity to find BC.
Activity: ΔABC is a `square` triangle.
∴ By Pythagoras theorem
AB2 + BC2 = AC2
∴ 25 + BC2 = `square`
∴ BC2 = `square`
∴ BC = `square`
Chapter: [0.02] Pythagoras Theorem
Complete the following activity to prove:
cotθ + tanθ = cosecθ × secθ
Activity: L.H.S. = cotθ + tanθ
= `cosθ/sinθ + square/cosθ`
= `(square + sin^2theta)/(sinθ xx cosθ)`
= `1/(sinθ xx cosθ)` ....... ∵ `square`
= `1/sinθ xx 1/cosθ`
= `square xx secθ`
∴ L.H.S. = R.H.S.
Chapter: [0.06] Trigonometry
If ΔABC ~ ΔPQR, AB : PQ = 4 : 5 and A(ΔPQR) = 125 cm2, then find A(ΔABC).
Chapter: [0.01] Similarity
In the above figure, m(arc DXE) = 105°, m(Arc AYC) = 47°, then find the measure of ∠DBE.
Chapter: [0.03] Circle
Draw a circle of radius 3.2 cm and centre 'O'. Take any point P on it. Draw tangent to the circle through point P using the centre of the circle.
Chapter: [0.04] Geometric Constructions
If sinθ = `11/61`, then find the value of cosθ using the trigonometric identity.
Chapter: [0.06] Trigonometry
In ΔABC, AB = 9 cm, BC = 40 cm, AC = 41 cm. State whether ΔABC is a right-angled triangle or not. Write reason.
Chapter: [0.02] Pythagoras Theorem
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In the above figure, chord PQ and chord RS intersect each other at point T. If ∠STQ = 58° and ∠PSR = 24°, then complete the following activity to verify:
∠STQ = `1/2` [m(arc PR) + m(arc SQ)]
Activity: In ΔPTS,
∠SPQ = ∠STQ – `square` ......[∵ Exterior angle theorem]
∴ ∠SPQ = 34°
∴ m(arc QS) = 2 × `square`° = 68° ....... ∵ `square`
Similarly, m(arc PR) = 2∠PSR = `square`°
∴ `1/2` [m(arc QS) + m(arc PR)] = `1/2` × `square`° = 58° ......(I)
But ∠STQ = 58° .....(II) (given)
∴ `1/2` [m(arc PR) + m(arc QS)] = ∠______ ......[From (I) and (II)]
Chapter: [0.03] Circle
Complete the following activity to find the coordinates of point P which divides seg AB in the ratio 3:1 where A(4, – 3) and B(8, 5).
Activity:
∴ By section formula,
∴ x = `("m"x_2 + "n"x_1)/square`,
∴ x = `(3 xx 8 + 1 xx 4)/(3 + 1)`,
= `(square + 4)/4`,
∴ x = `square`,
∴ y = `square/("m" + "n")`
∴ y = `(3 xx 5 + 1 xx (-3))/(3 + 1)`
= `(square - 3)/4`
∴ y = `square`
Chapter: [0.05] Co-ordinate Geometry
In ΔABC, seg XY || side AC. If 2AX = 3BX and XY = 9, then find the value of AC.
Chapter: [0.01] Similarity
Prove that "Opposite angles of a cyclic quadrilateral are supplementary".
Chapter: [0.03] Circle
ΔABC ~ ΔPQR. In ΔABC, AB = 5.4 cm, BC = 4.2 cm, AC = 6.0 cm, AB:PQ = 3:2, then construct ΔABC and ΔPQR.
Chapter: [0.01] Similarity
Show that: `tan "A"/(1 + tan^2 "A")^2 + cot "A"/(1 + cot^2 "A")^2 = sin"A" xx cos"A"`
Chapter: [0.06] Trigonometry
□ABCD is a parallelogram. Point P is the midpoint of side CD. seg BP intersects diagonal AC at point X, then prove that: 3AX = 2AC
Chapter: [0.01] Similarity
In the above figure, seg AB and seg AD are tangent segments drawn to a circle with centre C from exterior point A, then prove that: ∠A = `1/2` [m(arc BYD) - m(arc BXD)]
Chapter: [0.03] Circle
Find the co-ordinates of centroid of a triangle if points D(–7, 6), E(8, 5) and F(2, –2) are the mid-points of the sides of that triangle.
Chapter: [0.05] Co-ordinate Geometry
If a and b are natural numbers and a > b If (a2 + b2), (a2 – b2) and 2ab are the sides of the triangle, then prove that the triangle is right-angled. Find out two Pythagorean triplets by taking suitable values of a and b.
Chapter: [0.02] Pythagoras Theorem
Construct two concentric circles with centre O with radii 3 cm and 5 cm. Construct a tangent to a smaller circle from any point A on the larger circle. Measure and write the length of the tangent segment. Calculate the length of the tangent segment using Pythagoras' theorem.
Chapter: [0.02] Pythagoras Theorem
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