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प्रश्न
Answer the following question:
Find the distance of P(−1, 1) from the line 12(x + 6) = 5(y − 2)
उत्तर
The equation of line is
12(x + 6) = 5(y − 2)
∴ 12x + 72 = 5y − 10
∴ 12x − 5y + 82 = 0
∴ distance of P(−1, 1) from this line
= `|(12(-1) + (-5)(1) + 82)/sqrt((12)^2 + (-5)^2)|`
= `|(-12 - 5 + 82)/sqrt(144 + 25)|`
= 5 units.
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