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प्रश्न
Find the distance of the point A(−2, 3) from the line 12x − 5y − 13 = 0
उत्तर
The equation of the line is 12x − 5y − 13 = 0
∴ distance of the point A(− 2, 3) from this line
= `|(12(-2) + (-5)3 - 13)/sqrt((12)^2 + (5)^2)|`
= `|(-24 - 15 - 13)/sqrt(144 + 25)|`
= `52/13`
= 4 units.
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