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Assertion (A): In Young's double slit experiment all fringes are of equal width. Reason (R): The fringe width depends upon the wavelength of light (λ) used, the distance of the screen - Physics

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प्रश्न

  • Assertion (A): In Young's double slit experiment all fringes are of equal width.
  • Reason (R): The fringe width depends upon the wavelength of light (λ) used, the distance of the screen from the plane of slits (D) and slits separation (d).

विकल्प

  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true and Reason (R) is NOT the correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is also false.

MCQ

उत्तर

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).

Explanation:

Bright and dark fringes are produced as light travels through a slit in Young's double-slit experiment. Both the black and brilliant fringes are the same width as YDSE.

Statement 2 explanation: White light is used in Young's double-slit studies, and it is directed through the slit. Therefore, only brilliant and dark fringes may be seen utilising this source.

We know that fringe width is given by,

Width = `(lambdaD)/d`

Where,

λ = Wavelength of source used.

D = Distance between screen and slit.

d = Distance between slits.

As fringe width depends on all these factors so the fringe width remains constant.

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2022-2023 (March) Outside Delhi Set 1

संबंधित प्रश्न

In young’s double slit experiment, deduce the conditions for obtaining constructive and destructive interference fringes. Hence, deduce the expression for the fringe width.


Show that the fringe pattern on the screen is actually a superposition of slit diffraction from each slit.


Using monochromatic light of wavelength λ in Young’s double slit experiment, the eleventh dark fringe is obtained on the screen for a phase difference of ______.


Using analytical method for interference bands, obtain an expression for path difference between two light waves.


In Young’s double slit experiment to produce interference pattern, obtain the conditions for constructive and destructive interference. Hence deduce the expression for the fringe width.


Suppose white light falls on a double slit but one slit is covered by a violet filter (allowing λ = 400 nm). Describe the nature of the fringe pattern observed.


A plate of thickness t made of a material of refractive index µ is placed in front of one of the slits in a double slit experiment. (a) Find the change in the optical path due to introduction of the plate. (b) What should be the minimum thickness t which will make the intensity at the centre of the fringe pattern zero? Wavelength of the light used is \[\lambda.\] Neglect any absorption of light in the plate.


A thin paper of thickness 0.02 mm having a refractive index 1.45 is pasted across one of the slits in a Young's double slit experiment. The paper transmits 4/9 of the light energy falling on it. (a) Find the ratio of the maximum intensity to the minimum intensity in the fringe pattern. (b) How many fringes will cross through the centre if an identical paper piece is pasted on the other slit also? The wavelength of the light used is 600 nm.


A Young's double slit apparatus has slits separated by 0⋅28 mm and a screen 48 cm away from the slits. The whole apparatus is immersed in water and the slits are illuminated by red light \[\left( \lambda = 700\text{ nm in vacuum} \right).\] Find the fringe-width of the pattern formed on the screen.


In Young's double-slit experiment, the screen is moved away from the plane of the slits. What will be its effect on the following?

  1. The angular separation of the fringes.
  2. Fringe-width.

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