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Consider one mole of perfect gas in a cylinder of unit cross section with a piston attached (figure). - Physics

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प्रश्न

Consider one mole of perfect gas in a cylinder of unit cross section with a piston attached (figure). A spring (spring constant k) is attached (unstretched length L) to the piston and to the bottom of the cylinder. Initially the spring is unstretched and the gas is in equilibrium. A certain amount of heat Q is supplied to the gas causing an increase of volume from V0 to V1.

  1. What is the initial pressure of the system?
  2. What is the final pressure of the system?
  3. Using the first law of thermodynamics, write down a relation between Q, Pa, V, Vo and k.
दीर्घउत्तर

उत्तर

a. Initially the piston is in equilibrium hence, Pf = Pa

b. On supplying heat, the gas expands from V0 to V1

∴ Increase in volume of the gas = V1 – V0

As the piston is of the unit cross-sectional area hence, extension in the spring

`x = (V_1 - V_0)/"Area" = V_1 - V_0`

∴ Force exerted by the spring on the piston

= `F = kx = k(V_1 - V_0)`

Hence, Final pressure = `P_f = P_a + kx`

= `P_a + k xx (V_1 - V_0)`

c. From the first law of thermodynamics `dQ = du + dW`

If T is the final temperature of the gas. then increases in internal energy

`dU = C_v (T - T_0) = C_v (T - T_0)`

We can write, `T = (P_f V_1)/R - [(P_a + k(V_1 - V_0))/R] V_1/R`

Work done by the gas = PdV + increase in PE of the spring

= `P_a (V_1 - V_0) + 1/2 kx^2`

Now, we can write `dQ = dU + dW`

= `C_V (T - T_0) + P_a (V - V_0) + 1/2 kx^2`

= `C_V (T - T_0) + P_a (V_ V_0) + 1/2 (V_1 - V_0)^2`

This is the required relation.

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First Law of Thermodynamics
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Thermodynamics - Exercises [पृष्ठ ८९]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 12 Thermodynamics
Exercises | Q 12.27 | पृष्ठ ८९
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