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प्रश्न
Describe the locus of a point in rhombus ABCD, so that it is equidistant from
- AB and BC;
- B and D.
उत्तर
i.
The locus of the point in a rhombus ABCD which is equidistant from AB and BC will be the diagonal BD.
ii.
The locus of the point in a rhombus ABCD which is equidistant from B and D will be the diagonal AC.
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संबंधित प्रश्न
In each of the given figures; PA = PB and QA = QB.
i. | ![]() |
ii. | ![]() |
Prove, in each case, that PQ (produce, if required) is perpendicular bisector of AB. Hence, state the locus of the points equidistant from two given fixed points.
The given figure shows a triangle ABC in which AD bisects angle BAC. EG is perpendicular bisector of side AB which intersects AD at point F.
Prove that:
F is equidistant from A and B.
The bisectors of ∠B and ∠C of a quadrilateral ABCD intersect each other at point P. Show that P is equidistant from the opposite sides AB and CD.
Describe the locus for questions 1 to 13 given below:
1. The locus of a point at a distant 3 cm from a fixed point.
Describe the locus of points at distances less than or equal to 2.5 cm from a given point.
Describe the locus of points at distances greater than or equal to 35 mm from a given point.
Sketch and describe the locus of the vertices of all triangles with a given base and a given altitude.
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- the locus of the centres of all circles which touch AB and AC,
- the locus of the centres of all the circles of radius 2 cm which touch AB.
Hence, construct the circle of radius 2 cm which touches AB and AC .
Given: ∠BAC, a line intersects the arms of ∠BAC in P and Q. How will you locate a point on line segment PQ, which is equidistant from AB and AC? Does such a point always exist?
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