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Eliminate θ from the following: x = 3secθ , y = 4tanθ - Mathematics and Statistics

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प्रश्न

Eliminate θ from the following: 

x = 3secθ , y = 4tanθ

योग

उत्तर

x = 3sec θ and y = 4tan θ

∴ sec θ = `x/3 and tan theta = y/4`

We know that,

sec2θ – tan2θ = 1

∴ `(x/3)^2 - (y/4)^2` = 1

∴ `x^2/9 - y^2/16` = 1

∴ `(16x^2 - 9y^2)/(16 xx 9)` = 1

∴ `(16x^2 - 9y^2)/144` = 1

∴ 16x2 − 9y2 = 1 x 144

∴ 16x2 – 9y2 = 144

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Trigonometry - 1 - EXERCISE 2.2 [पृष्ठ ३१]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 2 Trigonometry - 1
EXERCISE 2.2 | Q 4) i) | पृष्ठ ३१

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