Advertisements
Advertisements
प्रश्न
Evaluate the following :
`(cot 40^@)/cos 35^@ - 1/2 [(cos 35^@)/(sin 55^@)]`
उत्तर
We have to find:
`(cot 40^@)/cos 35^@ - 1/2 [(cos 35^@)/(sin 55^@)]`
Since `cot(90^@ - theta) = tan theta` and `cos (90^@- theta) = sin theta`
`(cot 40^@)/(tan 50^@) - 1/2 ((cos 35^@)/(sin 55^@)) = cot(90^@ - 50^@)/ tan 50^@ - 1/2 (cos(90^@ - 55^@)/sin 55^@)`
`= tan 50^@/tan 50^@ - 1/2 ((sin 55^@)/(sin 55^@))`
`= 1 - 1/2`
`= 1/2`
So value of `(cot 40^@)/(tan 50^@) - 1/2 ((cos 35^@)/(sin 55^@)) " is " 1/2`
APPEARS IN
संबंधित प्रश्न
Evaluate the following in the simplest form: sin 60º cos 45º + cos 60º sin 45º
Prove the following
sin θ sin (90° − θ) − cos θ cos (90° − θ) = 0
Express each of the following in terms of trigonometric ratios of angles lying between 0° and 45°.
cosec54° + sin72°
If sin x = cos y; write the relation between x and y, if both the angles x and y are acute.
For any angle θ, state the value of: sin2 θ + cos2 θ
If `sqrt3` = 1.732, find (correct to two decimal place) the value of `(2)/(tan 30°)`
If A = 30°;
show that:
`(1 + sin 2"A" + cos 2"A")/(sin "A" + cos"A") = 2 cos "A"`
Without using tables, evaluate the following: tan230° + tan260° + tan245°
Find the value of x in the following: `sqrt(3)`tan 2x = cos60° + sin45° cos45°
The value of 5 sin2 90° – 2 cos2 0° is ______.
