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प्रश्न
Evaluate the following:
`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`
उत्तर
`(8/27)^((-2)/3) - (1/3)^-2 - 7^0`
= `(27/8)^(2/3) - (3)^2 - 1`
= `(3/2)^(3 xx 2/3) - 9 - 1`
= `(3/2)^2 - 10`
= `(9)/(4) - 10`
= `(9 - 40)/(4)`
= `(-31)/(4)`.
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