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Find the Area Enclosed by the Parabola 4y = 3x2 and the Line 2y = 3x + 12 - Mathematics

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प्रश्न

Find the area enclosed by the parabola 4y = 3x2 and the line 2y = 3x + 12

उत्तर

The area enclosed between the parabola, 4y = 3x2, and the line, 2y = 3x + 12, is represented by the shaded area OBAO as

The points of intersection of the given curves are A (–2, 3) and (4, 12).

We draw AC and BD perpendicular to x-axis.

∴ Area OBAO = Area CDBA – (Area ODBO + Area OACO)

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अध्याय 8: Application of Integrals - Exercise 8.3 [पृष्ठ ३७५]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 8 Application of Integrals
Exercise 8.3 | Q 7 | पृष्ठ ३७५

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