हिंदी

Find the Equation of the Hyperbola Whose Focus is (2, 2), Directrix Is X + Y = 9 and Eccentricity = 2. - Mathematics

Advertisements
Advertisements

प्रश्न

Find the equation of the hyperbola whose focus is (2, 2), directrix is x + y = 9 and eccentricity = 2.

संक्षेप में उत्तर

उत्तर

Let be the focus and  \[P\left( x, y \right)\] be any point on the hyperbola.
Draw PM perpendicular to the directrix.
By definition:
SP = ePM

\[\Rightarrow\] \[\sqrt{(x - 2 )^2 + (y - 2 )^2} = 2\left( \frac{x + y - 9}{\sqrt{2}} \right)\]

Squaring both the sides:

\[(x - 2 )^2 + (y - 2 )^2 = 4 \left( \frac{x + y - 9}{2} \right)^2 \]

\[ \Rightarrow x^2 - 4x + 4 + y^2 - 4y + 4 = 2\left( x^2 + y^2 + 81 + 2xy - 18y - 18x \right)\]

\[ \Rightarrow x^2 - 4x + 4 + y^2 - 4y + 4 = 2 x^2 + 2 y^2 + 162 + 4xy - 36y - 36x\]

\[ \Rightarrow x^2 + y^2 + 4xy - 32y - 32x + 154 = 0\]

∴ Equation of the hyperbola = \[x^2 + y^2 + 4xy - 32y - 32x + 154 = 0\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 27: Hyperbola - Exercise 27.1 [पृष्ठ १३]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
अध्याय 27 Hyperbola
Exercise 27.1 | Q 2.6 | पृष्ठ १३

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the equation of the hyperbola satisfying the given conditions:

Vertices (0, ±5), foci (0, ±8)


Find the equation of the hyperbola satisfying the given conditions:

Foci (0, ±13), the conjugate axis is of length 24.


Find the equation of the hyperbola satisfying the given conditions:

Foci `(+-3sqrt5, 0)`, the latus rectum is of length 8.


Find the equation of the hyperbola whose focus is (0, 3), directrix is x + y − 1 = 0 and eccentricity = 2 .


Find the equation of the hyperbola whose focus is (1, 1) directrix is 2x + y = 1 and eccentricity = \[\sqrt{3}\].


Find the equation of the hyperbola whose focus is (a, 0), directrix is 2x − y + a = 0 and eccentricity = \[\frac{4}{3}\].


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

9x2 − 16y2 = 144


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

16x2 − 9y2 = −144


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

 4x2 − 3y2 = 36


Find the eccentricity, coordinates of the foci, equation of directrice and length of the latus-rectum of the hyperbola .

2x2 − 3y2 = 5.


Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in  the  conjugate axis is 5 and the distance between foci = 13 .


Find the equation of the hyperbola whose vertices are (−8, −1) and (16, −1) and focus is (17, −1).


Find the equation of the hyperbola whose  foci are (4, 2) and (8, 2) and eccentricity is 2.


Find the equation of the hyperbola whose vertices are at (0 ± 7) and foci at \[\left( 0, \pm \frac{28}{3} \right)\] . 


Find the equation of the hyperboala whose focus is at (5, 2), vertex at (4, 2) and centre at (3, 2).


Find the equation of the hyperboala whose focus is at (4, 2), centre at (6, 2) and e = 2.


If P is any point on the hyperbola whose axis are equal, prove that SP. S'P = CP2.


Find the equation of the hyperbola satisfying the given condition :

vertices (± 2, 0), foci (± 3, 0)


Find the equation of the hyperbola satisfying the given condition :

 vertices (0, ± 5), foci (0, ± 8)


Find the equation of the hyperbola satisfying the given condition :

vertices (0, ± 3), foci (0, ± 5)


Find the equation of the hyperbola satisfying the given condition :

 foci (0, ± 13), conjugate axis = 24


find the equation of the hyperbola satisfying the given condition:

 vertices (± 7, 0), \[e = \frac{4}{3}\]


Find the equation of the hyperbola satisfying the given condition:

 foci (0, ± \[\sqrt{10}\], passing through (2, 3).


Write the equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0).


Equation of the hyperbola whose vertices are (± 3, 0) and foci at (± 5, 0), is


The foci of the hyperbola 2x2 − 3y2 = 5 are


The equation of the hyperbola whose centre is (6, 2) one focus is (4, 2) and of eccentricity 2 is


Find the equation of the hyperbola with vertices at (0, ± 6) and e = `5/3`. Find its foci.


Find the equation of the hyperbola whose vertices are (± 6, 0) and one of the directrices is x = 4.


Find the equation of the hyperbola with eccentricity `3/2` and foci at (± 2, 0).


The locus of the point of intersection of lines `sqrt(3)x - y - 4sqrt(3)k` = 0 and `sqrt(3)kx + ky - 4sqrt(3)` = 0 for different value of k is a hyperbola whose eccentricity is 2.


The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half of the distance between the foci is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×