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The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half of the distance between the foci is ______. - Mathematics

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प्रश्न

The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half of the distance between the foci is ______.

विकल्प

  • `4/3`

  • `4/sqrt(3)`

  • `2/sqrt(3)`

  • None of these

MCQ
रिक्त स्थान भरें

उत्तर

The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half of the distance between the foci is `2/sqrt(3)`.

Explanation:

Length of the latus rectum of the hyperbola

= `(2b^2)/a` = 8

⇒ b2 = 4a   .......(i)

Distance between the foci = 2ae

Transverse axis = 2a

And Conjugate axis = 2b

∴ `1/2(2ae) = 2b`

⇒ ae = 2b

⇒ b = `(ae)/2`   ......(ii)

⇒ `b^2 = (a^2e^2)/4`

⇒ `4a = (a^2e^2)/4`   ......[From equation (i)]

⇒ 16 = ae2

∴ `a = 16/e^2`

Now b2 = a2(e2 – 1)

⇒ 4a = a2(e2 – 1)

⇒ `4/a = e^2 - 1`

⇒ `4/(16/e^2) = e^2 - 1`

⇒ `e^2/4 = e^2 - 1`

⇒ `e^2 - e^2/4` = 1

⇒ `(3e^2)/4` = 1

⇒ `e^2 = 4/3`

∴ e = `2/sqrt(3)`

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अध्याय 11: Conic Sections - Exercise [पृष्ठ २०७]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 11 Conic Sections
Exercise | Q 57 | पृष्ठ २०७

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