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प्रश्न
Find the number of oscillations performed per minute by a magnet is vibrating in the plane of a uniform field of 1.6 × 10-5 Wb/m2. The magnet has a moment of inertia 3 × 10-6 kg/m2 and magnetic moment 3 A m2.
उत्तर
Data: B = 1.6 x 10-5 T, I = 3 x 10-6 kg/m2 , µ = 3 A m2
The period of oscillation, T = `2πsqrt("I"/(μ"B"_"h")`
∴ The frequency of oscillation is
f = `1/(2π)sqrt((μ"B")/("I"))`
∴ The number of oscillations per minute
= 60f = `60/(2π)sqrt((3(1.6xx10^-5))/(3xx10^-6))=60/(2π)sqrt(16)=120/3.142`
= 38.19 osc/min.
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