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Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches. - Mathematics

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प्रश्न

Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches.

योग

उत्तर

Let AB be a vertical wall and AC = 10 m is a ladder.

The top of the ladder reaches to A and distance of ladder from the base of the wall BC is 6 m.

In right angled ΔABC,

AC2 = AB2 + BC2   ...[By pythagoras theorem]

⇒ (10)2 = AB2 + (6)2

⇒ 100 = AB2 + 36

⇒ AB2 = 100 – 36 = 64

∴ AB = `sqrt(64)` = 8 cm

Hence, the height of the point on the wall where the top of the ladder reaches is 8 cm.

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अध्याय 6: Triangles - Exercise 6.3 [पृष्ठ ६९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 6 Triangles
Exercise 6.3 | Q 15 | पृष्ठ ६९

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