Advertisements
Advertisements
प्रश्न
If `"a" + 1/"a" = 6;`find `"a" - 1/"a"`
उत्तर
`("a" + 1/"a")^2`
= `("a"^2) + 2("a") (1/"a") + (1/"a")^2`
= `"a"^2 + (1)/"a"^2 + 2`
⇒ 36 = `"a"^2 + (1)/"a"^2 + 2`
⇒ `"a"^2 + (1)/"a"^2`
= 34
`("a" - 1/"a")^2`
= `("a")^2 - 2("a") (1/"a") + (1/"a")^2`
= `"a"^2 + 1/"a"^2 - 2`
= 34 - 2
= 32
⇒ `"a" - 1/"a"`
= ±`sqrt(32)`
= ± 4`sqrt(2)`.
APPEARS IN
संबंधित प्रश्न
Give possible expression for the length and breadth of the following rectangle, in which their area is given:
| Area : 35y2 + 13y – 12 |
Write in the expanded form:
`(a + 2b + c)^2`
If 3x − 2y = 11 and xy = 12, find the value of 27x3 − 8y3
Simplify of the following:
(2x − 5y)3 − (2x + 5y)3
If \[x^4 + \frac{1}{x^4} = 623\] then \[x + \frac{1}{x} =\]
Expand the following:
(x - 3y - 2z)2
Simplify by using formula :
(5x - 9) (5x + 9)
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`
If `"p" + (1)/"p" = 6`; find : `"p"^2 + (1)/"p"^2`
Multiply x2 + 4y2 + z2 + 2xy + xz – 2yz by (–z + x – 2y).
