If A2 - 3a - 1 = 0 and a ≠ 0, Find : a 2 − 1 a 2 - Mathematics

If a² - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`

योग

`"a"^2 - (1)/"a"^2`

= `("a" + 1/"a")("a" - 1/"a")`

= `(±sqrt(13)) (3)`
= ±3`sqrt(13)`.

shaalaa.com

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 4: Expansions - Exercise 4.1

अध्याय 4 Expansions
Exercise 4.1 | Q 16.3

Factorise the following using appropriate identity:

9x² + 6xy + y²

Evaluate the following using identities:

(1.5x²− 0.3y²) (1.5x²+ 0.3y²)

If 3x − 2y = 11 and xy = 12, find the value of 27x³ − 8y³

Evaluate of the following:

46³+34³

Find the following product:

(4x − 5y) (16x² + 20xy + 25y²)

If \[x^4 + \frac{1}{x^4} = 623\] then \[x + \frac{1}{x} =\]

If \[x^4 + \frac{1}{x^4} = 194,\] then \[x^3 + \frac{1}{x^3} =\]

If a + b + c = 9 and ab + bc + ca =23, then a³+ b³+ c³ − 3abc =

If `"p" + (1)/"p" = 6`; find : `"p"^2 + (1)/"p"^2`

Simplify:
(4x + 5y)² + (4x - 5y)²