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प्रश्न
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`
बेरीज
उत्तर
`"a"^2 - (1)/"a"^2`
= `("a" + 1/"a")("a" - 1/"a")`
= `(±sqrt(13)) (3)`
= ±3`sqrt(13)`.
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