Advertisements
Advertisements
प्रश्न
If the sides of a triangle are produced in order, then the sum of the three exterior angles so formed is
विकल्प
90°
180°
270°
360°
उत्तर
n the given ΔABC, all the three sides of the triangle are produced. We need to find the sum of the three exterior angles so produced.
Now, according to the angle sum property of the triangle
∠A + ∠B + ∠C = 180° .......(1)
Further, using the property, “an exterior angle of the triangle is equal to the sum of two opposite interior angles”, we get,
ext.∠C = ∠A + ∠B ......(2)
Similarly,
ext.∠A = ∠C + ∠B .......(3)
Also,
ext.∠B = ∠C+ ∠A .......(4)
Adding (2) (3) and (4)
We get,
ext.∠A + ext.∠B+ ext.∠C = ∠C+∠B +∠C +∠A + ∠B + ∠A
= 2(∠A= ∠B+ ∠C )
= 2 (180°)
= 360°
Thus, ext. ∠A + ext. ∠B ext.∠C = 360°
APPEARS IN
संबंधित प्रश्न
Two angles of a triangle are equal and the third angle is greater than each of those angles
by 30°. Determine all the angles of the triangle.
The exterior angles, obtained on producing the base of a triangle both way are 104° and 136°. Find all the angles of the triangle.
Compute the value of x in the following figure:
In ΔABC, ∠B = ∠C and ray AX bisects the exterior angle ∠DAC. If ∠DAX = 70°, then ∠ACB =
Find the unknown marked angles in the given figure:
Classify the following triangle according to sides:
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
7 cm, 24 cm, 25 cm
Find all the three angles of the ΔABC
Can you draw a triangle with 25°, 65° and 80° as angles?
Can we have two acute angles whose sum is a straight angle? Why or why not?