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प्रश्न
In a leap year the probability of having 53 Sundays or 53 Mondays is ______.
विकल्प
`2/7`
`3/7`
`4/7`
`5/7`
उत्तर
In a leap year the probability of having 53 Sundays or 53 Mondays is `3/7`.
Explanation:
Since a leap year has 366 days and hence 52 weeks and 2 days.
The 2 days can be SM, MT, TW, WTh, ThF, FSt, StS.
Therefore, P(53 Sundays or 53 Mondays) = `3/7`.
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संबंधित प्रश्न
Which of the following can not be valid assignment of probabilities for outcomes of sample space S = {ω1, ω2,ω3,ω4,ω5,ω6,ω7}
| Assignment | ω1 | ω2 | ω3 | ω4 | ω5 | ω6 | ω7 |
| (a) | 0.1 | 0.01 | 0.05 | 0.03 | 0.01 | 0.2 | 0.6 |
| (b) | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` | `1/7` |
| (c) | 0.1 | 0.2 | 0.3 | 0.4 | 0.5 | 0.6 | 0.7 |
| (d) | –0.1 | 0.2 | 0.3 | 0.4 | -0.2 | 0.1 | 0.3 |
| (e) | `1/14` | `2/14` | `3/14` | `4/14` | `5/14` | `6/14` | `15/14` |
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| (ii) |
\[\frac{1}{7}\]
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\[\frac{1}{7}\]
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\[\frac{1}{7}\]
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\[\frac{1}{7}\]
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\[\frac{1}{7}\]
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\[\frac{1}{7}\]
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\[\frac{1}{7}\]
|
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