Advertisements
Advertisements
प्रश्न
In a ∆ABC, ∠A = 90°, AB = 5 cm and AC = 12 cm. If AD ⊥ BC, then AD =
विकल्प
- \[\frac{13}{2}cm\]
- \[\frac{60}{13}cm\]
- \[\frac{13}{60}cm\]
- \[\frac{2\sqrt{15}}{13}cm\]
उत्तर
Given: In ΔABC, `∠ A = 90^o` AD ⊥ BC, AC = 12cm, and AB = 5cm.
To find: AD
We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.
In ∆ACB and ∆ADC,
We got the result as `b`.
APPEARS IN
संबंधित प्रश्न
A girl of height 90 cm is walking away from the base of a lamp-post at a speed of 1.2m/sec. If the lamp is 3.6 m above the ground, find the length of her shadow after 4 seconds.
A point D is on the side BC of an equilateral triangle ABC such that\[DC = \frac{1}{4}BC\]. Prove that AD2 = 13 CD2.
In a quadrilateral ABCD, ∠B = 90°. If AD2 = AB2 + BC2 + CD2 then prove that ∠ACD = 90°.
In the given figure, DE || BC and \[AD = \frac{1}{2}BD\]. If BC = 4.5 cm, find DE.
The areas of two similar triangles ∆ABC and ∆DEF are 144 cm2 and 81 cm2 respectively. If the longest side of larger ∆ABC be 36 cm, then the longest side of the smaller triangle ∆DEF is
If D, E, F are the mid-points of sides BC, CA and AB respectively of ∆ABC, then the ratio of the areas of triangles DEF and ABC is
If ∆ABC is an equilateral triangle such that AD ⊥ BC, then AD2 =
In an equilateral triangle ABC if AD ⊥ BC, then
∆ABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm. If ∆DEF ∼ ∆ABC and EF = 4 cm, then perimeter of ∆DEF is
If ∆ABC ∼ ∆DEF such that DE = 3 cm, EF = 2 cm, DF = 2.5 cm, BC = 4 cm, then perimeter of ∆ABC is
