Advertisements
Advertisements
प्रश्न
In a ΔABC, AD is the bisector of ∠A.
If AB = 10cm, AC = 14cm and BC = 6cm, find BD and DC.
उत्तर
It is given that AD bisects ∠𝐴.
Applying angle – bisector theorem in Δ ABC, we get:
`(BD)/(DC)=(AB)/(AC)`
Let BD be x cm.
Therefore, DC = (6- x) cm
⟹ `x/(6-x)=10/14`
⟹14x = 60-10x
⟹24x = 60
⟹x = 2.5 cm
Thus, BD = 2.5 cm
DC = 6-2.5 = 3.5 cm
APPEARS IN
संबंधित प्रश्न
In ∆PQR, M and N are points on sides PQ and PR respectively such that PM = 15 cm and NR = 8 cm. If PQ = 25 cm and PR = 20 cm state whether MN || QR.
Corresponding sides of two triangles are in the ratio 2 : 3. If the area of the smaller triangle is 48 cm2, determine the area of the larger triangle.
The diagonals of quadrilateral ABCD intersect at O. Prove that
`[A(∆"ACB")]/[A(∆"ACD")] = "BO"/"DO"`
In ∆ABC, AD is a median. Prove that AB2 + AC2 = 2AD2 + 2DC2.
In the figure given below DE || BC. If AD = 2.4 cm, DB = 3.6 cm, AC = 5 cm. Find AE.
If ABC and DEF are similar triangles such that ∠A = 57° and ∠E = 73°, what is the measure of ∠C?
The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is ______.
The areas of two similar triangles ∆ABC and ∆DEF are 144 cm2 and 81 cm2 respectively. If the longest side of larger ∆ABC be 36 cm, then the longest side of the smaller triangle ∆DEF is
In ∆ABC, a line XY parallel to BC cuts AB at X and AC at Y. If BY bisects ∠XYC, then
If ∆ABC ∼ ∆DEF such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ∆DEF is 25 cm, then the perimeter of ∆ABC is
