Advertisements
Advertisements
प्रश्न
If ∆ABC ∼ ∆DEF such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ∆DEF is 25 cm, then the perimeter of ∆ABC is
विकल्प
36 cm
30 cm
34 cm
35 cm
उत्तर
Given: ΔABC is similar to ΔDEF such that AB= 9.1cm, DE = 6.5cm. Perimeter of ΔDEF is 25cm.
To find: Perimeter of ΔABC.
We know that the ratio of corresponding sides of similar triangles is equal to the ratio of their perimeters.
Hence,
`(AB)/(DE)=(BC)/(EF)=(AC)/(DE)=(P1)/(P2)`
`(AB)/(DE)=(P(Δ ABC))/(P(Δ DEF))`
`9.1/6.5=(P(Δ ABC))/25`
`P(Δ ABC)=(9.1xx25)/6.5`
`P(Δ ABC)=35cm`
Hence the correct answer is `d`
APPEARS IN
संबंधित प्रश्न
D and E are points on the sides AB and AC respectively of a ΔABC. In each of the following cases, determine whether DE║BC or not.
AD = 5.7cm, DB = 9.5cm, AE = 4.8cm and EC = 8cm.
A 13m long ladder reaches a window of a building 12m above the ground. Determine the distance of the foot of the ladder from the building.
In the given figure, DE || BD. Determine AC and AE.
In the given figure, each of PA, QB, RC and SD is perpendicular to l. If AB = 6 cm, BC = 9 cm, CD = 12 cm and PS = 36 cm, then determine PQ, QR and RS.
Prove that in an equilateral triangle, three times the square of a side is equal to four times the square of its altitudes.
In a quadrilateral ABCD, given that ∠A + ∠D = 90°. Prove that AC2 + BD2 = AD2 + BC2.
In ∆ABC, ∠ABC = 135°. Prove that AC2 = AB2 + BC2 + 4 ar (∆ABC)
If ∆ABC and ∆DEF are similar such that 2AB = DE and BC = 8 cm, then EF =
The areas of two similar triangles are 121 cm2 and 64 cm2 respectively. If the median of the first triangle is 12.1 cm, then the corresponding median of the other triangle is
In the given figure, if ∠ADE = ∠ABC, then CE =
