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In the following figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that: ΔAEP ∼ ΔADB - Mathematics

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प्रश्न

In the following figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:

ΔAEP ∼ ΔADB

योग

उत्तर

In ΔAEP and ΔADB,

∠AEP = ∠ADB       ...(Each 90°)

∠PAE = ∠DAB       ...(Common)

Hence, by using AA similarity criterion,

ΔAEP ∼ ΔADB

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अध्याय 6: Triangles - Exercise 6.3 [पृष्ठ १४०]

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