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प्रश्न
In the following figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:
ΔABD ∼ ΔCBE
उत्तर
In ΔABD and ΔCBE
∠ADB = ∠CEB = 90°
∠ABD = ∠CBE ....(Common angle)
Hence, by using the AA similarity criterion,
ΔABD ∼ ΔCBE
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