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In the following figure, DE || AC and DC || AP. Prove that : BEEC=BCCP. - Mathematics

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प्रश्न

In the following figure, DE || AC and DC || AP. Prove that : `(BE)/(EC) = (BC)/(CP)`.

योग

उत्तर

In the given figure,

DE || AC and DC || AP

To prove: `(BE)/(EC) = (BC)/(CP)`

Proof: In ΔBCA, we have

ED || CA

Since a line drawn is || to one side of a Δ divides the other two side proportionality.

∴ `(BE)/(EC) = (BD)/(DA)`   ...(i)

Similarly in ΔBPA; we have DC || AP

Since a line drawn is || to one side of a Δ divides the other two side proportionality.

∴ `(BC)/(CP) = (BD)/(DA)`   ...(ii)

From (i) and (ii),

`(BE)/(EC) = (BC)/(CP)`

Hence proved.

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Areas of Similar Triangles Are Proportional to the Squares on Corresponding Sides
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Similarity (With Applications to Maps and Models) - Exercise 15 (E) [पृष्ठ २३०]

APPEARS IN

सेलिना Mathematics [English] Class 10 ICSE
अध्याय 15 Similarity (With Applications to Maps and Models)
Exercise 15 (E) | Q 9 | पृष्ठ २३०

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