Advertisements
Advertisements
प्रश्न
In the given figure, ABCD is a cyclic quadrilateral. AF is drawn parallel to CB and DA is produced to point E. If ∠ADC = 92°, ∠FAE = 20°; determine ∠BCD. Give reason in support of your answer.
उत्तर
In cyclic quad. ABCD,
AF || CB and DA is produced to E such that ∠ADC = 92° and ∠FAE = 20°
Now, we need to find the measure of ∠BCD
In cyclic quad. ABCD,
`=>` ∠B + ∠D = 180°
`=>` ∠B + 92° = 180°
`=>` ∠B = 180° – 92°
`=>` ∠B = 88°
Since AF || CB, ∠FAB = ∠B = 88°
But, ∠FAE = 20° ...[Given]
Ext. ∠BAE = ∠BAF + ∠FAE
= 88° + 20°
= 108°
But, Ext. ∠BAE = ∠BCD
∴ ∠BCD = 108°
APPEARS IN
संबंधित प्रश्न
In the figure given, O is the centre of the circle. ∠DAE = 70°. Find giving suitable reasons, the measure of:
- ∠BCD
- ∠BOD
- ∠OBD
In the given figure PQRS is a cyclic quadrilateral PQ and SR produced meet at T
1) Prove ΔTPS ~ ΔTRQ.
2) Find SP if TP = 18 cm, RQ = 4 cm and TR = 6 cm
3) Find the area of quadrilateral PQRS if the area of ΔPTS = 27 cm2.
Use the given figure to find:
- ∠BAD,
- ∠DQB.
ABCDE is a cyclic pentagon with centre of its circumcircle at point O such that AB = BC = CD and angle ABC = 120°.
Calculate:
- ∠BEC
- ∠BED
In the following figure, ABCD is a cyclic quadrilateral in which AD is parallel to BC.
If the bisector of angle A meets BC at point E and the given circle at point F, prove that:
- EF = FC
- BF = DF
MABN are points on a drde having centre O. AN and MB cut at Y. If ∠ NYB = 50" and ∠ YNB = 200, find ∠ MAN and reflex angle MON.
In the figure, O is the centre of the circle and the length of arc AB is twice the length of arc BC. If angle AOB = 108°, find: ∠ADB.
In the given below the figure, O is the centre of the circle and ∠ AOC = 160°. Prove that 3∠y - 2∠x = 140°.
If O is the centre of the circle, find the value of x in each of the following figures
In the given figure O is the center of the circle, ∠ BAD = 75° and chord BC = chord CD. Find:
(i) ∠BOC (ii) ∠OBD (iii) ∠BCD.