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Prove that the line joining the mid-points of the diagonals of a trapezium is parallel to the parallel sides of the trapezium. - Mathematics

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प्रश्न

Prove that the line joining the mid-points of the diagonals of a trapezium is parallel to the parallel sides of the trapezium.

योग

उत्तर

Given: Let ABCD be a trapezium in which AB || DC and let M and N be the mid-points of the diagonals AC and BD, respectively.


To prove: MN || AB || CD

Construction: Join CN and produce it to meet AB at E.

In ΔCDN and ΔEBN, we have

DN = BN   ...[Since, N is the mid-point of BD]

∠DCN = ∠BEN   ...[Alternate interior angles]

And ∠CDN = ∠EBN  ...[Alternate interior angles]

∴ ΔCDN ≅ ΔEBN  ...[By AAS congruence rule]

∴ DC = EB and CN = NE   ...[By CPCT rule]

Thus, in ΔCAE, the points M and N are the mid-points of AC and CE, respectively.

∴ MN || AE   ...[By mid-point theorem]

⇒ MN || AB || CD

Hence proved.

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अध्याय 8: Quadrilaterals - Exercise 8.4 [पृष्ठ ८३]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 9
अध्याय 8 Quadrilaterals
Exercise 8.4 | Q 17. | पृष्ठ ८३

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