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Prove the following: cos27∘+sin27∘cos27∘-sin27∘ = tan72° - Mathematics and Statistics

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प्रश्न

Prove the following:

`(cos27^circ + sin27^circ)/(cos27^circ - sin27^circ)` = tan72°

योग

उत्तर

L.H.S. = `(cos27^circ + sin27^circ)/(cos27^circ - sin27^circ)` 

= `((cos27^circ)/(cos27^circ) + (sin27^circ)/(cos27^circ))/((cos27^circ)/(cos27^circ) - (sin27^circ)/(cos27^circ))`

= `(1 + tan27^circ)/(1 - tan27^circ)`

= `(tan45^circ + tan27^circ)/(1 - tan45^circ xx tan27^circ)`   ...[∵  tan45° = 1]

= tan(45° + 27°)

= tan72°

= R.H.S.

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Trigonometric Functions of Triple Angle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometry - 2 - Exercise 3.1 [पृष्ठ ३९]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board
अध्याय 3 Trigonometry - 2
Exercise 3.1 | Q 2. (xi) | पृष्ठ ३९

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