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Solve the following problem : Following tables shows the wheat yield (‘000 tonnes) in India for years 1959 to 1968.Fit a trend line to the above data by the method of least squares. - Mathematics and Statistics

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प्रश्न

Solve the following problem :

Following tables shows the wheat yield (‘000 tonnes) in India for years 1959 to 1968.

Year 1959 1960 1961 1962 1963 1964 1965 1966 1967 1968
Yield 0 1 2 3 1 0 4 1 2 10

Fit a trend line to the above data by the method of least squares.

योग

उत्तर

In the given problem, n = 10 (even), two middle t – value are 1963 and 1964, h = 1

u = `"t - mean of two middle values"/("h"/2) = ("t" - 1963.5)/(1/2)` = 2(t – 1963.5)

We obtain the following table.

Year
t
Yield
(in '000 tonnes) 

yt
u = 2(t – 1963.5) u2 uyt Trend Value
1959 0 –9 81 0 –0.1632
1960 1 –7 49 –7 0.4064
1961 2 –5 25 –10 0.9760
196 3 –3 9 –9 1.5456
1963 1 –1 1 –1 2.1152
1964 0 1 1 0 2.6848
1965 4 3 9 12 3.2544
1966 1 5 25 5 3.8240
1967 2 7 49 14 4.3936
1968 10 9 81 90 4.9632
Total 24 0 330 94  

From the table, n = 10, `sumy_"t" = 24, sumu = 0, sumu^2 = 330,sumuy_"t" = 94`

The two normal equations are: `sumy_"t" = "na"' + "b"' sumu  "and" sumuy_"t", = a'sumu + b'sumu^2`

∴ 24 = 10a' + b'(0)               ...(i)   and
94 = a'(0) + b'(330)              ...(ii)

From (i), a' = `(24)/(10)` = 2.4

From (ii), b' = `(94)/(330)` = 0.2848
∴  The equation of the trend line is yt = a' + b'u
i.e., yt = 2.4 + 0.2848 u, where u = 2(t – 1963.5).

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Measurement of Secular Trend
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Time Series - Miscellaneous Exercise 4 [पृष्ठ ७०]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] 12 Standard HSC Maharashtra State Board
अध्याय 4 Time Series
Miscellaneous Exercise 4 | Q 4.19 | पृष्ठ ७०

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