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प्रश्न
The periodic time of a linear harmonic oscillator is 2π second, with maximum displacement of 1 cm. If the particle starts from extreme position, find the displacement of the particle after π/3 seconds.
उत्तर
Given:-
`a=1cm,t=pi/3s,omega=(2pi)/T=(2pi)/(2pi)=1`
To find: Displacement (x)
Formula: x = A cos ωt
Calculation: From formula,
`"x"=1cos(1xxpi/3)=cos(pi/3)`
`therefore"x"=0.5cm`
The displacement of the particle after π/3 seconds is 0.5 cm.
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