Advertisements
Advertisements
प्रश्न
Use tables to find sine of 62° 57'
उत्तर
sin 62° 57' = sin (62° 54' + 3')
= 0.8902 + 0.0004
= 0.8906
APPEARS IN
संबंधित प्रश्न
If sin θ =3/5, where θ is an acute angle, find the value of cos θ.
if `tan theta = 12/5` find the value of `(1 + sin theta)/(1 -sin theta)`
Evaluate.
`(sin77^@/cos13^@)^2+(cos77^@/sin13^@)-2cos^2 45^@`
Find the sine ratio of θ in standard position whose terminal arm passes through (3, 4)
Write the value of tan 10° tan 15° tan 75° tan 80°?
The value of \[\frac{\cos^3 20°- \cos^3 70°}{\sin^3 70° - \sin^3 20°}\]
Find the value of the following:
`(cos 70^circ)/(sin 20^circ) + (cos 59^circ)/(sin31^circ) + cos theta/(sin(90^circ - theta))- 8cos^2 60^circ`
Choose the correct alternative:
If ∠A = 30°, then tan 2A = ?
In ∆ABC, cos C = `12/13` and BC = 24, then AC = ?
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.
