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The Value of Cos 3 20 ° − Cos 3 70 ° Sin 3 70 ° − Sin 3 20 ° - Mathematics

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प्रश्न

The value of \[\frac{\cos^3 20°- \cos^3 70°}{\sin^3 70° - \sin^3 20°}\] 

विकल्प

  • \[\frac{1}{2}\]

  • \[\frac{1}{\sqrt{2}}\]

  •  1

MCQ

उत्तर

We have to evaluate the value. The formula to be used, 

`a^3+b^3=(a+b)(a^2+b^2-ab)` 

`a^3-b^3=(a-b)(a^2+b^2+ab)` 

So, 

=`(cos^3 20°-cos 70)/(sin^3 70°-sin^3 20)`

=` ((cos 20°-cos 70)(cos^2 20°+cos^2 70+cos 20° cos 70°))/((sin 70°-sin 20°)(sin^2 70°+sin^2 20°+sin 70° sin 20°))`

Now using the properties of complementary angles, 

= `((sin 70°- sin  20°)(sin^2 70°+cos^2 70+cos 20° cos 70°))/((sin 70°-sin 20°)(sin ^2 70°+cos ^2 70°+sin 70° sin 20°))`

=`(1+cos 20° cos 70°)/(1+sin 70° sin 20°)` 

=`( 1+ cos20° cos 70°)/(1+cos 20° cos 70°)`

=1

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अध्याय 10: Trigonometric Ratios - Exercise 10.5 [पृष्ठ ५७]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 10 Trigonometric Ratios
Exercise 10.5 | Q 12 | पृष्ठ ५७

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